FT Multi Entry Tournaments

I would think this would greatly lessen the incentive to multi-account. It has close to the same benefits of mult-accounting and the HUGE upside that you don't have to worry about being caught and having your winning confiscated.

Didn't follow the first part of this one, but maybe I don't understand mult-entries. If I multi-enter a MTT and get 2 seats at the FT (or is this where my stacks are merged? But since you mention 1st and 9th, I'm thinking not), why couldn't I, theoretically, sit out and get down to the final 3 seats at least?

I tend to agree with the poster who said they've given up on controlling multi-accounters and "legalized" cheating.

At the final table, your stacks are automatically merged. There is no sitting out.

It's not cheating if it is legal.

So when the multi-entry "players" reach final 9 and stacks are merged, one of them gets 9th place in the process? Is that where the 1st and 9th comes in?

And, t, sure it's not cheating if it's legal. But where multi-accounters are illegal by definition, a whip of the pencil made mult-entries, albeit with the same account (a pure technical distinction IMO), made it legal.

So when the multi-entry "players" reach final 9 and stacks are merged, one of them gets 9th place in the process? Is that where the 1st and 9th comes in?

And, t, sure it's not cheating if it's legal. But where multi-accounters are illegal by definition, a whip of the pencil made mult-entries, albeit with the same account (a pure technical distinction IMO), made it legal. There was no fundamental poker rationale it seems to me that makes MTTs better (the business rationale is obvious, more enrtries, more $). It's just making it legit.

Yes, you are always at a different table than yourself, until that is no longer possible. So if you have 3 entries, and the play goes down to two tables, you'd also have one stack merged with the other stack (I don't know how they choose, probably the smaller two are merged). Obviously, when the stacks are merged, one goes to zero, so that entry is eliminated and gets the corresponding payout.