Tonight, on videopoker.com, I was playing 10-Play Triple Double Bonus Poker. I was dealt the ace, 2, 3, and 5 of diamonds, and the ace of spades. Given the chances of an inside straight flush against what four aces (particularly with the kicker) pays on Triple Double, I held the two aces, which I believe was the right hold. After the draw, the first card in three out of the 10 hands had, in fact, the 4 of diamonds. So I would have connected on three straight flushes had I kept the four- card straight flush. I’m trying to calculate the odds of this result and the nearest I can compute is 1/47 times 1/47 times 1/47 (since the three hands were independent events) or approximately 1 in 103,000.
[Editor’s Note: The answer to this question is provided by the inimitable Bob Dancer, whose blog can be found on our sister site, Gambling with an Edge, where you can also hear a weekly podcast in which Bob and Richard Munchkin, author of our book Gambling Wizards, interview likely subjects.]
You’ve managed to ask a lot of questions in one QOD. Let’s get started.
First, the inside straight flush is the better play by a mile. Yes, four aces with a kicker pays a bunch, but you only get that 1-in-1,622 times from that position. Holding AA from that position in Triple Double Bonus ($10.16) isn’t worth much more than holding in it Double Double Bonus ($9.50). (How much you get for the flush is irrelevant insofar as the value of the aces is concerned, but it does affect the value of the straight-flush draw, as you had 8/47 draws from there that would have given you a flush.) If you concentrate on just the aces, it seems like it should be a much bigger difference, but you end up with 3-of-a-kind about one time in nine — and that pays only $10 in TDB, while it pays $15 in DDB.
Any good video poker software will give you this information. I recommendVideo Poker for Winners, but there are others.
If you’re confused about this hand, which isn’t that difficult, you’re probably making mistakes on a lot of other hands as well. VPW also provides a strategy for the game. Use it, rather than trying to figure it out by your own methods.
Second, the 1-in-103,000 figure you cite would be appropriate if you were playing Triple Play, where you had to connect on the 1/47 shot on each line. In Ten Play, it doesn’t particularly matter which three lines you get it on. The appropriate mathematical function to compute this is called the Binomial Theorem.
This is not an appropriate place for an extended lesson on the Binomial Theorem, but if you use the BINOMDIST function on an Excel spreadsheet, you’ll find out that the odds for hitting three or more 1/47 shots in 10 tries is about 1-in-1,000, not 1-in-103,000.
Insofar as whether you would have hit all three perfect draws had you correctly held the straight flush draw like you did when you held the aces, there’s a very slim chance that would have happened. The draws take place when you hit the button — down to the nanosecond. Unless you hit the button at precisely the same time, you would have gotten a totally different draw on all 10 hands.
Finally, worrying about what you would have gotten this time if you played it the other way is a fool’s game. You have to make your choice and take what you get from that choice. Whatever happened this particular time is a small bit of data and is not a very good predictor of what will happen next time, or the next next time, or the … Go with the math rather than spending time dwelling on what happened this particular time.
Then again, if it makes you happy to feel bad that the other draw would have worked out better this time, go right ahead. Your feelings won’t change the results one bit. But if that’s how you want to spend your time and energy, be my guest.
|
[email protected]
May-29-2017
|
|
Jeff
May-29-2017
|
|
George
May-29-2017
|
|
Jeff
May-29-2017
|
|
Steven Larson
May-29-2017
|
|
SkeeterMN49
May-29-2017
|
|
Jim Veith
May-29-2017
|
|
Steven Larson
May-30-2017
|
|
Annie
May-31-2017
|