I bought the new edition of Gambling 102 by the Wizard of Odds, Michael Shackleford. I liked the old edition (mostly to settle arguments over gambling math with my friends), but I wanted to check the new games covered in the book. But while I was leafing through it, I noticed that double-zero roulette has a 5.26% casino edge, while single-zero is 2.70%. Why wouldn't it be 2.63%, exactly half of 5.26%?
Glad you like Gambling 102 second edition. The new games in the book that you refer to, for everyone's benefit, are Crazy 4 Poker, Face Up Pai Gow Poker, High Card Flush, Mississippi Stud, Pai Gow (tiles), and Texas Hold 'em Bonus.
To answer your question, the difference is in the denominator in the equation that determines the edge.
Say you bet red in a game with two zeros. There are 36 numbers plus the zeros, making a total of 38 slots on the wheel. Of them, 18 (the reds) are winners and 20 (18 blacks and two zeros) are losers. That's a result of -2 units in 38 plays, yielding the equation -2/38 = -5.26%.
On a single-zero wheel, there are only 19 losers, meaning you lose only 1 unit, which would seem to indicate an edge of -1/38 = -2.63% (as you suggest).
However, removing the second zero leaves only 37 total slots, so the equation is -1/37 = 2.7%.
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Dave
Feb-03-2020
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rokgpsman
Feb-03-2020
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Kevin Lewis
Feb-03-2020
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Dave in Seattle.
Feb-07-2020
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